Question

what must be subtracted from(3x^2+4y^2-5) to get (2x^2-3y^2+5)

Answer 1

Answer:

(3x^2+4y^2-5)-(2x^2+3y^2+5)

=(x^2+y^2-10) must be subtracted

hope it helps you

Answer 2

Answer:

x^2 + 7y^2 - 10 must be subtracted from(3x^2+4y^2-5) to get (2x^2-3y^2+5)

Hopes it will be help you.

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