Math, asked by viduola, 1 year ago

what must be subtracted from 3x²-4y²-5z²-6 to get 4x²+5y²-6z²+7

Answers

Answered by rishabh54

12

3x²-4y²-5z²-6-n=4x²+5y²-6z²+7
n=3x²-4y²-5z²-6-4x²-5y²+6z²-7
n=-x²-9y²+z²-13

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