Question

what must be subtracted from 3x²-4y²-6to get 4x²+5y²-6z²+7?​

Answer 1

Answer:

Let m be subtracted from 3x²-4y²-6.

(3x²-4y²-6)-(m) = 4x²+5y²-6z²+7

-m = 4x²+5y²-6z²+7-(3x²-4y²-6)

-m = 4x²+5y²-6z²+7-3x²+4y²+6

-m = 4x²-3x²+5y²+4y²-6z²+7+6

-m = x²+9y²-6z²+13

m = -(x²+9y²-6z²+13)

m = -x²-9y²+6z²-13

Hope it helps you...

Answer 2

Answer:

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