What must be subtracted from 3x2 – 6xy – 3y2 – 1 to get 4x2 – 7xy - 4y2 +1 ? with solution
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Answer:
let's put X
give:-
- =(3x²-6xy-3y²-1) + X = 4x²-7xy-4y²+1
- = X= ( 4x²-7xy-4y²+1) - (3x²-6xy-3y²-1) (by transposing LHS to RHS)
- so, X= x²-xy-y²+2
hence, if we will subtract x²-xy-y²+2 from 3x²-6xy-3y²-1
we will get 4x²-7xy-4y²+1
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