Question

what must be subtracted from 3x²-6xy-3y²-1 to get 4x²-7xy-4y²+1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let q should be subtracted.

Let q should be subtracted.Then according to question,

Let q should be subtracted.Then according to question,3x

Let q should be subtracted.Then according to question,3x 2

Let q should be subtracted.Then according to question,3x 2 −4y

Let q should be subtracted.Then according to question,3x 2 −4y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x 2 +x 2−4y 2 +y2+5xy−6xy+20−20

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x 2 +x 2−4y 2 +y2+5xy−6xy+20−20⇒q=4x 2 −3y 2

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x 2 +x 2−4y 2 +y2+5xy−6xy+20−20⇒q=4x 2 −3y 2 −xy+0

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x 2 +x 2−4y 2 +y2+5xy−6xy+20−20⇒q=4x 2 −3y 2 −xy+0Hence, 4x

Let q should be subtracted.Then according to question,3x 2 −4y 2 +5xy+20−q=−x 2 −y 2 +6xy+20⇒q=3x 2 −4y 2 +5xy+20−(−x 2 −y 2 +6xy+20)⇒q=3x 2 −4y 2 +5xy+20+x 2 +y 2 −6xy−20⇒q=3x 2 +x 2−4y 2 +y2+5xy−6xy+20−20⇒q=4x 2 −3y 2 −xy+0Hence, 4x 2−3y 2−xy should be subtracted.