Math, asked by balli07, 4 months ago


What must be subtracted from 4a? + 5b2-6c2 + 8 to get 2a2-3b2-4c2-5​

Answers

Answered by Tasmiapanda
0

Answer:

4a+5b²-6c²+8 - 2a²-3b²-4c²-5 = 4a+2b²-10c²+3

4a+2b²-10c²+3 should be subtracted from

4a+5b²-6c²+8 to get -2a²-3b²-4c²-5 .

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