Math, asked by dhritvanshahi, 9 months ago

what must be subtracted from 4x^4-2x^3-6x^2+2x+6

Answers

Answered by Mehekjain
7

<font color=purple>

 \huge \bold {Your questionisincomplete}

Answered by Nivedita4209
4

Answer:

2x^2 + x - 2.

(4x^4 - 2x^3 - 6x^2 + x -5) divided by (2x^2 + x - 2) gives a quotient of 2x^2 - 2x and a remainder of -3x-5.

So you need to subtract (-3x-5) from the dividend.

Check: (4x^4 - 2x^3 - 6x^2 + x -5) -(-3x-5)

= 4x^4 - 2x^3 - 6x^2 + x -5 + 3x + 5

= (4x^4 - 2x^3 - 6x^2 + 4x) divided by (2x^2 + x - 2) gives a quotient of 2x^2 - 2x and a remainder of 0. Correct.

So you need to subtract (-3x-5) from the dividend.

Similar questions