what must be subtracted from 4x^4-2x^3-6x^2+x-5 so that the result is exactly divisible by 4x^2+2x
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7
Answer:
We divide 4x
4
−2x
3
−6x
2
+x−5 by 2x
2
+x−1 as shown in the below image:
From the division, we observe that the quotient is 2x
2
−2x−1 and the remainder is −6.
Hence, −6 should be subtracted from 4x
4
−2x
3
−6x
2
+x−5 so that result is exactly divisible by 2x
2
+x−1.
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