Question

What must be subtracted from 4x^4-2x^3-6x^2 +x-5so that the result is exactly divisible by 2x^2 +3x-2 ?

Please answer correctly ​

Answer 1

Answer:

-3x-5

Explanation:

will re-write the dividend and divisor as 4x^4 - 2x^3 - 6x^2 + x -5 and

-52x^2 + x - 2.

(4x^4 - 2x^3 - 6x^2 + x -5) divided by (2x^2 + x - 2) gives a quotient of 2x^2 - 2x and a remainder of -3x-5.

So you need to subtract (-3x-5) from the dividend.

Check: (4x^4 - 2x^3 - 6x^2 + x -5) -(-3x-5)

= 4x^4 - 2x^3 - 6x^2 + x -5 + 3x + 5

= (4x^4 - 2x^3 - 6x^2 + 4x) divided by (2x^2 + x - 2) gives a quotient of 2x^2 - 2x and a remainder of 0. Correct.

So you need to subtract (-3x-5) from the dividend.

Answer 2

Answer:

refer to the attachment for your answer

hope it helps

pls mark as brainlliest