Question

What must be subtracted from 4x4 - 3x3 + 2x2 + x
- 1 so that the result is exactly divisible by 2x2 +
X - 1?​

Answer 1

Answer:

Answer-

Let the number that subtracted be x

According to Question,

(4x4 - 3x3 + 2x2 + x) - x = x / 2x2 +X - 1

4x⁴ - 3x³ + 2x² + x = x/2x² + x - 1

2x² + x - 1 (4x⁴ - 3x³ + 2x² + x ) = x

8x^6 - 6x^5 + 4x⁴ + 2x³ + 4x^5 - 3x⁴ + 2x³+x² - 4x⁴ + 3x³ - 2x² - x = x

Hope it will be helpful :)

Answer 2

Explanation:

Let the number be subtracted from x

so,

$4 \times 4 - 3 \times 3 + 2 \times 2 + x - x = \frac{x}{2 \times 2} + x - 1$

${4x}^{4} - {3x}^{3} + {2x }^{2} + x = \frac{x}{? {2x}^{2} } + x - 1$

${2x}^{2} + x - 1( {4x}^{4} - {3x}^{ 3} + {2x}^{2} + x = x$

${8x}^{6} - {6x}^{5} + {4x}^{4} + {2x}^{3} + {4x}^{5} - {3x}^{4} + {2x}^{3} + {x}^{2} - {4x}^{4} + {3x}^{3} + {2x}^{2} - x = x$