Math, asked by ansh6948, 5 hours ago

What must be subtracted from 5 whole 1 upon 6 to get 2 whole 11 upon 18​

Answers

Answered by ichchhakuichchha
2

let the unknown number is X

a/q

X-31/6=47/18

X=47/18+31/6

X=(47+93)/18

X=140/18

X=70/9

Answered by nandanipatel20605
1

Answer:

46/18 =x

5 whole 1uopn 6= 31/6

2whole 11 upon 18= 47/18

let the number which is to be subtracted be 'x'

so, according to the given question;

31/6 - x = 47/18

31/6 - 47/18= x

taking the lcm of 6 and 18 i.e. 18

31x3/6x3 - 47/18 = x

93-47/18 = x

46/18 =x

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