What must be subtracted from 5 whole 1 upon 6 to get 2 whole 11 upon 18
Answers
Answered by
2
let the unknown number is X
a/q
X-31/6=47/18
X=47/18+31/6
X=(47+93)/18
X=140/18
X=70/9
Answered by
1
Answer:
46/18 =x
5 whole 1uopn 6= 31/6
2whole 11 upon 18= 47/18
let the number which is to be subtracted be 'x'
so, according to the given question;
31/6 - x = 47/18
31/6 - 47/18= x
taking the lcm of 6 and 18 i.e. 18
31x3/6x3 - 47/18 = x
93-47/18 = x
46/18 =x
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