Question

What must be subtracted from ( 5a^2 -16ab -3b^2 -1 ) to get ( 6a^2 -3ab -4b^2 + 1)

Answer 1

Answer:

-a^2-13ab+b^2-2

Step-by-step explanation:

so let no. be substracted be x

( 5a^2 -16ab -3b^2 -1 )-x=( 6a^2 -3ab -4b^2 + 1)

x= ( 5a^2 -16ab -3b^2 -1 )-( 6a^2 -3ab -4b^2 + 1)

x= 5a^2 -16ab -3b^2 -1- 6a^2 +3ab +4b^2 - 1

x= 5a^2- 6a^2 -16ab+3ab  -3b^2  +4b^2-1-1

x=-a^2-13ab+b^2-2 ans.

Hope it is helpful!!

Answer 2

Answer:

a^2 + 13ab - b^2 +2

Step-by-step explanation:

[5a^2 - 16ab - 3b^2-1] - x = [6a^2 - 3ab - 4b^2 +1]

x = [6a^2 - 3ab - 4b^2 +1] - [5a^2 - 16ab - 3b^2-1]

x = 6a^2 - 5a^2 -3ab +16ab - 4b^2 + 3b^2 +1 +1

  x = a^2 + 13ab - b^2 +2