Question

What must be subtracted from 5a²-16ab-3b²-1 to get 6a²-3ab-4b²+1​

Answer 1

Answer:

Please mark me brainliest.

Answer 2

Let polynomial be x

5a²-16ab-3b²-1-x=6a²-3ab-4b²+1

x= (5a²-16ab-3b²-1)-(6a2-3ab-4b²+1)

x=5a²-16ab-3b²-1-6a²+3ab+4b²-1

x=-a²-13ab+b²-2

hope this helps

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