What must be subtracted from 5n² - 18n + 30 to get 2n² + 4n + 23?
PLSSSSSS i realy need it now
Answers
Answered by
0
Answer:
Let the number to be subtracted from each term be x
According to the question
33−x
17−x
=
15
7
255−15x=231−7x
15x−7x=255−231
8x=24
x=3
Therefore, 3 to be sutracted from each term of the ratio 17:30 so that the ratio becomes 7:15
Answered by
1
Answer:
Let a be the first term and d be the common difference of an A.P. then sum
of n terms (Sn) = n/2.[2.a+(n-1).d].
S14= -203…………..(1)
14/2[2a+(14–1).d]= -203
2a+13d= - 29………….(2)
S25-S14 = -572……….(3). putting S14= -203 in eqn. (3)
S25+203 = -572
S25= -775
25/2[2a+(25–1)d] = -775
2a+24d=-775×2/25= - 31×2
2a+24d = -62………….(4).
Subtracting eqn. (2) from eqn. (4)
11d= -33. => d=-3. and. 2a -39=-29. =>. a= 5
Thus , the A.P. is:-
5 , 2 , -1 , -4 , -7 , -10 ,………………. Answer.
Similar questions