Question

What must be subtracted from 5x2-2xy-3y2-1 to get 6x2+3xy-5y2+7.​

Answer 1

Answer:

-x2 +5xy -2y2 +8 should be subtracted

Answer 2

$\large\underline\purple{\bold{Solution :- }}$

• Let 'z' be subtracted.

So,

$\rm :\implies\: {5x}^{2} - 2xy - {3y}^{2} - 1 - z = {6x}^{2} + 3xy - {5y }^{2} + 7$

$\rm :\implies\:z = {5x}^{2} - 2xy - {3y}^{2} - 1 - ({6x}^{2} + 3xy - {5y }^{2} + 7)$

$\rm :\implies\:z = {5x}^{2} - 2xy - {3y}^{2} - 1 - {6x}^{2} - 3xy + {5y }^{2} - 7$

$\rm :\implies\:z = (5 {x}^{2} - {6x}^{2} ) + ( - 2xy - 3xy) + ( - {3y}^{2} + {5y}^{2} ) + ( - 1 - 7)$

$\rm :\implies\:z = - {x}^{2} - 5xy + {2y}^{2} - 8$