Question

what must be subtracted from 6a² square minus 15a to get - 41 a²​

Answer 1

Answer:

Let X be subtracted from 3a

2

−6ab−3b

2

Then,

3a

2

−6ab−3b

2

−1−X=4a

2

−7ab−4b

2

+1

x=3a

2

−6ab−3b

2

−1−(4a

2

−7ab−4b

2

+1)

x=3a

2

−6ab−3b

2

−1−4a

2

+7ab+4b

2

−1

x=−a

2

+ab+b

2

−2