What must be subtracted from 8xcube+7xsqy-3xysq-y to get 7xysq-ycube-3xsqy+5xcube?
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4
Answer:
3x³ - y³ - 3xy²+ 3x²y + 7x² - y
Step-by-step explanation:
Let the number that need to be subtracted be N.
So, 8x³ + 7x² - 3xy² - y - N = y³ - 3x²y + 5x³
⇒ N = 8x³ + 7x² - 3xy² - y - (y³ - 3x²y + 5x³)
⇒ N = 8x³ + 7x² - 3xy² - y - y³ + 3x²y - 5x³
⇒ N = 3x³ - y³ - 3xy²+ 3x²y + 7x² - y
So, the number that needs to be subtracted is 3x³ - y³ - 3xy²+ 3x²y + 7x² - y
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