Math, asked by kesharwaniritika3, 11 months ago

What must be subtracted from 8xcube+7xsqy-3xysq-y to get 7xysq-ycube-3xsqy+5xcube?​

Answers

Answered by naavyya
4

Answer:

3x³ - y³ -  3xy²+ 3x²y + 7x² - y

Step-by-step explanation:

Let the number that need to be subtracted be N.

So,  8x³ + 7x² - 3xy² - y - N = y³ - 3x²y + 5x³

⇒ N = 8x³ + 7x² - 3xy² - y  - (y³ - 3x²y + 5x³)  

⇒  N = 8x³ + 7x² - 3xy² - y  - y³ + 3x²y - 5x³

⇒ N =  3x³ - y³ -  3xy²+ 3x²y + 7x² - y

So, the number that needs to be subtracted is 3x³ - y³ -  3xy²+ 3x²y + 7x² - y

Answered by Anonymous
3

Step-by-step explanation:

click on it

hope this helps

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