What must be subtracted from a^3b + 6a^2 b^2-7 a b + 4 to get - 7a^2 b +2a^3b + 6 a b - 1 ?
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Step-by-step explanation:
3a
2
−6ab−3b
2
−1)−s=(4a
2
−7ab−4b
2
+1)
⇒s=(3a
2
−6ab−3b
2
−1)−(4a
2
−7ab−4b
2
+1)
⇒s=3a
2
−6ab−3b
2
−1−4a
2
+7ab+4b
2
−1
⇒s=(3a
2
−4a
2
)+(−6ab+7ab)+(−3b
2
+4b
2
)+(−1−1)
⇒s=−a
2
+ab−b
2
−2
Therefore, −a
2
+ab+b
2
−2 must be subtracted from 3a
2
−6ab−3b
2
−1 to get 4a
2
−7ab−4b
2
+1.
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