What must be subtracted from a square + b square + c square minus 3 ABC to get to a square minus b square minus 3 c square + a b c
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Answered by
4
Answer:
a2+b2+c2-3abc=(a+b+c)(a2-b2-c2-2ab-2bc-2ca)
=(0)(a2-b2-c2-2ab-2bc-2ca)(a+b+c=0)
=0
a2+b2+c2=-3abc
Answered by
0
Answer:
Answer is 0
Step-by-step explanation:
because indentiteas is alway s answer is 0
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