Question

What must be subtracted from a3 – 4a2 + 5a – 6 to obtain a2 – 2a + 1 ? step by step​

Answer 1

Let the expression to be subtracted be X.

X.(a3 − 4a2 + 5a − 6)-X = (a2 − 2a + 1)

Since '-' sign precedes the parenthesis, we remove it and change the sign of each term within the parenthesis.

X = a3 − 4a2 + 5a − 6- a2 + 2a - 1Rearranging and collecting the like terms:

X = a3 +(− 4-1)a2 + (5+2)a − 6 - 1X = a3 −5a2 + 7a − 7

• So, a3 −5a2 + 7a − 7 must be subtracted from a3 − 4a2 + 5a − 6 to obtain a2 − 2a + 1.

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Answer 2

Answer:

To get that you have substract a2-2a+1 from a3-4a2+5a-6.

a3 -4a2+5a-6

(-) a2-2a+1..

a3 -5a2 +7a -7

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