Question

What must be subtracted from a3b +6a2 b2 -7ab +4 to get -7a2 b2 +2a3b+6ab-1

Answer 1

Answer:

number the number be X

ATQ,

x-(a3b+6a2b2 - 7ab + 4)= -7a2b2+2a3b+6ab-1

x-a3b-6a2b2+7ab-4=-7a2b2+2a3+6bab-1

X=2a3b+a3b-7a2b2+6a2b2+6ab-7ab-1+4

X=8a3b-a2b2-ab+3