Question

what must be subtracted from each of the numbers 17, 25, 31, 47 so that the remainders may be in proportion ?

Answer 1

Number given 17, 25, 31, 47
assume that x is subtracted from each of the number
17-x, 25-x, 31-x, 47-x are in proportion
(17-x)/ (25-x )= (31-x)/ (47-x)
(17-x) (47-x) = (25-x ) (31-x)
799-17x-47x+x2 = 775-25x-31x+x2
-64x+799 = -56x+775
8x = 24
x=3
so, 3 must be subtracted from each of the number

Answer 2

Answer:

Step-by-step explanation:

17/25 = 31/47-------(not in proportion)
17-x/25-x = 31-x/47-x
(17-x)(47-x) = (25-x)(31-x)
799-17x-47x+x^2 = 775-25x-31x+x^2
799-64x = 775-56x
-64x-56x = 775-799
-8x = -24
x = -24/-8
x = 3