what must be subtracted from each of the numbers 17,25,31,47 so that the remainders may be in proportion.
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Answered by
22
assume that x is subtracted from each of the number17-x, 25-x, 31-x, 47-x are in proportion (17-x)/ (25-x )= (31-x)/ (47-x) (17-x) (47-x)
= (25-x ) (31-x) 799-17x-47x+x2 = 775-25x-31x+x2-64x+799
= -56x+775 8x = 24
x=3
so, 3 must be subtracted from each of the number
If you like it follow me and punch the brainiest button in the face
= (25-x ) (31-x) 799-17x-47x+x2 = 775-25x-31x+x2-64x+799
= -56x+775 8x = 24
x=3
so, 3 must be subtracted from each of the number
If you like it follow me and punch the brainiest button in the face
venuarvind:
thank u
Answered by
4
number given 17 25 31 47 assume that x is subtracted from each of the no 17-x 25-x 31-x 47-x are in propotion (17-x) (25-x)=(31-x) (47-x) (17-x) (47x)=(25x)=(31-x)=799-17x -4x+2x=775 8x =24x =3 so 3 must be subtracted from each of the no
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