Question

What must be subtracted from each of the numbers 23, 40, 57 and 108 so that the
resulting numbers are in proportion?​

Answer 1

Answer:

6

Step-by-step explanation:

Let the number to be subtracted from the given numbers be x.

Now, the remaining numbers are (23−x),(40−x),(57−x) and (108−x).

It is given that the remaining numbers are in the proportions.

So, (23−x):(40−x)::(57−x):(108−x)

(23−x)(40−x)=(57−x)(108−x)

Using the cross-multiplication method,

(23−x)(108−x)=(57−x)(40−x)

Multiply on both sides,

23∗108−23x−108x+x2=40∗57−57x−40x+x2

2484−131x+x2=2280−97x+x2

2484−131x=2280−97x

2484−2280=131x−97x

204=34x

204/ 34=x

x=6

Kindly mark it as brainliest.