what must be subtracted from p3 square - 2p+7p-6 to obtained 3p square -2p+3
Answers
Answered by
4
Step-by-step explanation:
3p² - 2p+3-(p3²+5p-6)= 3p²-2p+3-p3²-5p+6
=3p²-p3²-7p+9
Answered by
0
Step-by-step explanation:
=p3- 2p2 + 7p- 6 - ( 3p2- 2p+3)
= p3- 2p2 + 7p - 6- 3p2 + 2p - 3
= p3 - 5p2 + 9p - 9 . Answer
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