what must be subtracted from the numbers 23,40,57 and 108 so the remainder are in proportion.
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Step-by-step explanation:
Let the no. To be subtracted be x . Then ,
(23-x):(40-x)::(57-x):(108-x)
=(23-x)/(40-x)=(57-x)/(108-x)
=(23-x)(108-x)=(40-x)(57-x)
=2484-131x+2x=2280-97+2x
=34x=204 =
x = 204/34=6
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