Math, asked by sanskarmandal1, 6 months ago

what must be subtracted from the sum of 5x-3y+1 and 8y+4x-10 to get 10y-11

Answers

Answered by manya252590

0

Step-by-step explanation:

Let the no. to be subtracted = x

So, [5x-3y+1 + ( 8y+4x-10 )] - x = 10y-11

5x-3y+1+8y+4x-10-x = 10y-11

5x-x+4x +8y-3y -10+1 = 10y-11

8x + 5y - 9 = 10y-11

8x+5y-10y = -11 +9

8x-5y = -2

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