Question

What must be subtracted from x^3-3x-12x+19 so that the result is exactly divisible by x ^2 +x-6​

Answer 1

Answer:

-2x - 5 should be subtracted

Step-by-step explanation:

$\frac{ {x}^{3} - 3 {x}^{2} - 12x + 19 }{ {x}^{2} + x - 6 } = (x - 4) \frac{ - 2x - 5}{ {x}^{2} + x - 6 }$

hope you get your answer