What must be subtracted from x^3-6x^2-15x+80 so that the result is exactly divisible by x^2+x-12
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it is the question of polynomials
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when we divide (x^3-6x^2-15x+80)/(x^2+x-12) ,we will get the remainder 3x^2+128
Therefore 3x^2+128 will be subtracted from it to make it divisible by x^2+x-12
Therefore 3x^2+128 will be subtracted from it to make it divisible by x^2+x-12
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