what must be subtracted from x^4 + 2x^2 - 3x + 7 to get x^3 + x^2 + x - 1
Answers
Answered by
6
Answer:
x⁴ - x³ + x² - 4x + 8
Step-by-step explanation:
(x⁴ + 2x² - 3x + 7) - A = (x³ + x² + x - 1)
A = (x⁴ + 2x² - 3x + 7) - (x³ + x² + x - 1)
A = x⁴ + 2x² - 3x + 7 - x³ - x² - x + 1
A = x⁴ - x³ + x² - 4x + 8
Answered by
7
Answer:
Here goes the solution!
Subtracting x3 + x2 + x - 1 from x4 + 2x2 - 3x + 7
= x4 + 2x2 - 3x + 7 + x3 + x2 + x - 1
= x4 + x3 + 2x2 + x2 - 3x + x + 7 - 1
= x4 + x3 + 3x2 - 2x + 6
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