what must be subtracted from (x^4+2x^3-2x^2+4x+6) so that the result is exactly divisible by (x^2+2x-3)?
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YASHOFFICIAL24082004:
Thanks but answer is wrong
Answered by
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Let p(x) = x^4 + 2x^3 - 2x^2 + 4x + 6
Let g(x) = x^2 + 2x - 3.
We need to divide f(x) by g(x).
x^2 + 1
-----------------------------------------------
x^2 + 2x - 3) x^4 + 2x^3 - 2x^2 + 4x + 6
x^4 + 2x^3 - 3x^2
--------------------------------------------------
x^2 + 4x + 6
x^2 + 2x - 3
--------------------------------------------------
2x + 9.
Thus, the expression x^4 + 2x^3 - 2x^2 + 4x + 6 is exactly divisible by x^2 + 2x - 3 when 2x + 9 is subtracted from it.
Hope this helps!
Let g(x) = x^2 + 2x - 3.
We need to divide f(x) by g(x).
x^2 + 1
-----------------------------------------------
x^2 + 2x - 3) x^4 + 2x^3 - 2x^2 + 4x + 6
x^4 + 2x^3 - 3x^2
--------------------------------------------------
x^2 + 4x + 6
x^2 + 2x - 3
--------------------------------------------------
2x + 9.
Thus, the expression x^4 + 2x^3 - 2x^2 + 4x + 6 is exactly divisible by x^2 + 2x - 3 when 2x + 9 is subtracted from it.
Hope this helps!
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