what must be subtracted from x^4+2x^3-2x^2+4x+6 so that the result is exactly divisible by x^2+2x-3?
Answers
First we will divide x⁴ + 2x³ - 2x² + 4x +6 by x² +2x - 3
x² + 1
x² +2x - 3 ∫ x⁴ + 2x³ - 2x² + 4x +6
x⁴ + 2x³ - 3x²
x² + 4x + 6
x² + 2x - 3
2x + 9
So we should subratract the reminder 2x + 9
x⁴ + 2x³ - 2x² + 4x +6 - 2x - 9 = x⁴ + 2x³ - 2x² + 2x -3
x⁴ + 2x³ - 2x² + 2x -3 can be divide by x² +2x - 3
Answer:
the expression x^4 + 2x^3 - 2x^2 + 4x + 6 is exactly divisible by x^2 + 2x - 3 when 2x + 9 is subtracted from it.
Step-by-step explanation: