What must be subtracted from x^4+3x^3+4x^2+3x-6 to get 3x^3+4x^2-x+3
Answers
Answered by
1
The answer is 9-x^4+3
& this answer is verified by me..
No chances of being wrong for this one....
& this answer is verified by me..
No chances of being wrong for this one....
Answered by
2
Hey there !!!!
Let the polynomial which must be subtracted from x⁴+3x³+4x²-3x-6 to get
3x³+4x²-x+3 be "P".
So according to question :
x⁴+3x³+4x²-3x-6 - (P) = 3x³+4x²-x+3
(P) = x⁴+3x³+4x²-3x-6 -(3x³+4x²-x+3)
P = x⁴+3x³+4x²-3x-6-3x³-4x²+x-3
P=x⁴+3x³-3x³+4x²-4x²-3x+x-6-3
P=x⁴-2x-9
So x⁴-2x-9 must be subtracted from x⁴+3x³+4x²-3x-6 to get 3x³+4x²-x+3.
Hope this helped you.........
Let the polynomial which must be subtracted from x⁴+3x³+4x²-3x-6 to get
3x³+4x²-x+3 be "P".
So according to question :
x⁴+3x³+4x²-3x-6 - (P) = 3x³+4x²-x+3
(P) = x⁴+3x³+4x²-3x-6 -(3x³+4x²-x+3)
P = x⁴+3x³+4x²-3x-6-3x³-4x²+x-3
P=x⁴+3x³-3x³+4x²-4x²-3x+x-6-3
P=x⁴-2x-9
So x⁴-2x-9 must be subtracted from x⁴+3x³+4x²-3x-6 to get 3x³+4x²-x+3.
Hope this helped you.........
Similar questions