what must be subtracted from x/y to get y/x
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Answered by
20
@
let the no. be à
x/y-a=y/x
-a=y/x-x/y
-a=y²-x²/xy
a=x²-y²/xy
@:-)
let the no. be à
x/y-a=y/x
-a=y/x-x/y
-a=y²-x²/xy
a=x²-y²/xy
@:-)
Saumitra123:
thanx
Answered by
18
Let the number be 'a'
What must be subtracted from x/y to get y/x?
'a' must be subtracted from x/y to get y/x,
x/y - a = y/x
a = x/y-y/x
a = (x²-y²)/xy
Therefore,
(x²-y²)/xy must be subtracted from x/y to get y/x.
Hope it helps....
What must be subtracted from x/y to get y/x?
'a' must be subtracted from x/y to get y/x,
x/y - a = y/x
a = x/y-y/x
a = (x²-y²)/xy
Therefore,
(x²-y²)/xy must be subtracted from x/y to get y/x.
Hope it helps....
That was helpful too
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