Question

what must be subtracted from y⁴+2y²-3y+7 to get y³+y²-y-1​

Answer 1

Answer:

y⁴-y³+y²-2y+8

Step-by-step explanation:

Let the required equation be x

Now,

y⁴+2y²-3y+7-x= y³+y²-y-1

x=y⁴-y³+2y²-y²-3y+y+7+1

=>y⁴-y³+y²-2y+8