What must be subtracted from y4+2y2
-3y+7 to get y3+y2+y-1
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Answer:
= y4-y3+y2-4y+8
Step-by-step explanation:
y4+2y2-3y+7-(y3+y2+y-1). y4+2y2-3y+7-y3-y2-y+1. y4-y3+y2-4y+8
vijay0981:
sorry answer is -y3-4y+8
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