What must be the min electronegativity difference for a compound to be ionic
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Subtract the lower electronegativity value from the higher to find the difference between the two. In the case of HBr, the difference is 2.8 - 2.1 = 0.7. Multiply value you calculated by 100 to obtain the percentage of ionic character of the bond.
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Heyaa!!
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=>Electronegativity differences of 1.8 or greater lead to ionic bonding. The electronegativity difference is so great that one atom can attract the electrons enough to "take" them from the other atom.
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