What must be true of the value of ΔG° for a reaction ifa. K > 1b. K = 1c. K < 1
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The Product conducting automatic reaction...
constant must be K>1
constant must be K>1
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Dear Student,
◆ Answer -
a) For K > 1, ∆G° = Negative
b) For K = 1, ∆G° = Zero
c) For K < 1, ∆G° = Positive
● Explaination -
As we ∆G° is related to equilibrium constant by relation -
∆G° = -RT.lnK
a) For K > 1
When K > 1, lnK = +ve
Hence, ∆G° = -ve
b) For K = 1
When K = 1, lnK = 0
Hence, ∆G° = O
c) For K < 1
When K < 1, lnK = -ve
Hence, ∆G° = +ve
Hope this helps you...
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