Question

What net force is required to bring a 2500 kg car to rest from a speed of 100m/s in 8.0seconds?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Net\:Force=31250\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: car (M)= 2500 \: kg \\ \\ \tt: \implies Initial \: speed(u) = 100 \: m/s \\ \\ \tt: \implies Time(t) = 8 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Net \: Force \: require \: to \: stop =$

• According to given question :

$\tt \circ \: Initial \:speed = 100 \: m/s \\ \\ \tt \circ \: Final \: speed = 0 \: m/s \\ \\ \tt \circ \: Time = 8 \: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt : \implies v = u + at \\ \\ \tt : \implies 0 = 100 + a \times 8 \\ \\ \tt : \implies - 100 = a \times 8 \\ \\ \tt : \implies a = \frac{ - 100}{8} \\ \\ \green{\tt : \implies a = - 12.5 \: {m/s}^{2} } \\ \\ \bold{For \: Net \: force : } \\ \tt : \implies F = Ma \\ \\ \tt : \implies F= 2500 \times - 12.5 \\ \\ \green{\tt : \implies F= - 31250 \: N} \\ \\ \green{\tt \therefore Magnitude \: of \: net \: force \: required \:is \: 31250 \: N}$

Answer 2

...

$\tt{\huge{ \purple{ .................... }}}$

QUESTION -

What net force is required to bring a 2500 kg car to rest from a speed of 100m/s in 8.0seconds?

SOLUTION -

See the above attachment.