what no must be added from each of 14,22.,32 and 49 to make then proportional
can any one please explain the whole sum step by step it would be very helpful
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what no must be added from each of 14,22.,32 and 49 to make then proportional can any one please explain the whole sum step by step it would be very helpful
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What number should be added to each of 6, 14, 18 and 38 so that the resulting numbers make a proportion?
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You can write a proportion. If we let x = the number that should be added, then we can write: (6 + x)/(14 + x) = (18 + x)/(38 + x). If we cross multiply, we get the equation (6 + x)(38 + x) = (14 + x)(18 + x). FOILING each side of the last equation, we get 228 + 44x + x squared (that is, x times x) = 252 + 32x +x squared. If we subtract x squared from each side, we have 228 + 44x = 252 + 32x. Now subtract 32x from each side, we get 228 + 12x = 252. Next, subtract 228 from each side of this last equation and get 12x = 24. Finally, divide both sides by 12 to get x = 2. Check: Adding 2 to each of the original numbers, we get 8, 16, 20, and 40. These numbers are proportional since 8/16 = 20/40 (each of these ratios are equal to 1/2).
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