Question

what no.s should be subtracted from each of the no.s 23, 30, 57 and 78 so that the remainders are in proportion​

Answer 1

Answer:

6 is the number to be subtracted from 23, 30, 57, and 78, so that they become proportional.

Step-by-step explanation:

Let the number to be subtracted be x.

Then, according to the Question,

(23 - x)/(30 - x) = (57 - x)/(78 - x)

Cross multiplying we get,

(23 - x)(78 - x) = (30 - x)(57 - x)

1794 - 23x - 78x + x² = 1710 - 30x - 57x + x²

x² - x² - 101x + 1794 = 1710 - 87x

1794 - 101x = 1710 - 87x

101x - 87x = 1794 - 1710

14x = 84

x = 84/14

x = 6

Hence,

6 is the number to be subtracted from 23, 30, 57, and 78, so that they become proportional.

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