Question

What no. should be added to -3/4 to get 4/3

Answer 1

Answer

-3/4+x =4/3

-3+4x/4=4/3

-3+4x =4/3×4

-3+4x =16/3

4x=16/3+3

4x = 16+9/3

x=25/3×4

x=25/12

there fore 25/12 is to be added to get 4/3

Answer 2

Answer:

Required number $2 \frac{1}{12}$ should be added to -3/4 to get 4/3

Step-by-step explanation:

Given two numbers are $( - \frac{3}{4} ) \: and \: ( \frac{4}{3} )$

Here question is what number should be added to $( - \frac{3}{4} )$ to get $\frac{4}{3}$

Let the number be x.

According to question,

$- \frac{3}{4} + x = \frac{4}{3}$

We are separating variable and constant part,

$x = \frac{4}{3} + \frac{3}{4} \\ x = \frac{4 \times 4 + 3 \times 3}{12} \\ x = \frac{16 + 9}{12} \\ x = \frac{ 25 }{12} \\ x = 2 \frac{1}{12}$

This is a problem of Algebra.

Some important Algebra formulas

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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