Question

what no. should be added to each of the numbers 3,5,13 and 19 so that the resulting number be in proportion?​

Answer 1

Answer:

Let the number added be x

(3+x)/(5+x) = (13+x)/(19+x)

By cross multiply

(3+x)(19+x) = (13+x) (5+x)

57 + 22x +x^2 = 65 + 18x + x^2

22x - 18x = 65 - 57

4x = 8

X = 2

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Answer 2

Answer:

Let the number added be=x

(3+x)/(5+x) = (13+x)/(19+x)

By cross multiply

We get=(3+x)(19+x) = (13+x) (5+x)

Which is =57 + 22x +x^2 = 65 + 18x + x^2

Then,  22x - 18x = 65 - 57

=4x = 8

=X = 2

Step-by-step explanation: