What no should be added to x^2-5x+4 so that 3 becomes its 0?
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Answer:
p(x) = x^2-5x+4
p(3) = 3^2-5*3+4
=9-13+4
=0
therefore,nothing should be added to x^2-5x+4 so that 3 becomes its zero
Step-by-step explanation:
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