Question

What no. should be subtracted from 5/9 to get 1/3 ?
please answer the question ☝
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Answer 1

$\large\sf\underline{Question}$

What number should be subtracted from $\sf\:\frac{5}{9}$ to get $\sf\:\frac{1}{3}$ ?

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$\large\sf\underline{Assumption}$

• Let the number to be subtracted be x .

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$\large\sf\underline{Solution}$

According to the question :

$\sf⟹\:x-\frac{5}{9}=\frac{1}{3}$

• Finding LCM of 1 and 9

$\sf⟹\:\frac{9x-5}{9}=\frac{1}{3}$

• Cross multiplying

$\sf⟹\:3(9x-5)=9×1$

$\sf⟹\:27x-15=9$

$\sf⟹\:27x=9+15$

$\sf⟹\:27x=24$

$\sf⟹\:x=\frac{24}{27}$

So the required number is found to be ${\sf{{\pink{\frac{24}{27}}}}}$.

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$\small\rm\purple\star\:\underline{Verifying\:my\:answer}$

$\sf⟹\:\frac{24}{27}-\frac{5}{9}=\frac{1}{3}$

$\sf⟹\:\frac{(1×24)-(3×5)}{27}=\frac{1}{3}$

$\sf⟹\:\frac{24-15}{27}=\frac{1}{3}$

$\sf⟹\:\frac{9}{27}=\frac{1}{3}$

$\sf⟹\:\frac{1}{3}=\frac{1}{3}$

$\dag\:{\sf [Hence\:verified] \:}$

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!! Hope it helps !!