What number increased by its reciprocal equals 65/8 ?
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Do this by Middle Term Break Method.
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To find:
The number increased by its reciprocal is equal to 65/8.
Solution:
- Let the number be x and its reciprocal is 1/x.
- Therefore,
x + 1/x = 65/8
(x² + 1 ) / x = 65/8
8x² + 8 = 65 x
8x² - 65x + 8 = 0
8x² - 64x - x + 8 = 0
8x(x-8) - 1(x-8) = 0
(x-8) (8x -1) = 0
- Thus, x = 8 or x = 1/8
- Therefore the answer is 8 and 1/8.
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