Question

what number is that of which the third part exceeds the fifth part by 4?

Answer 1

$let \: required \: no. \: be \: x \: then \: atq \\ \frac{x}{3} = \frac{x}{5} + 4 \\ \frac{x}{3} - \frac{x}{5} = 4 \\ \frac{5x - 3x}{15} = 4 \\ 2x = 60 \\ x = 30 \: ........answer$

Answer 2

Hello friend

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consider number = x

given data

third part =x/3

fifth part=x5

x/3 - x/5 = 4

LCM

( 5x - 3x )/ 15 = 4

2x/15 = 4

x/15 =2

x= 30           ∴ (15*2)


Hence required Number = 30

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hope it's help u