Math, asked by vallamullaprasad25, 7 months ago

what number must be added in each term of the fraction 7/31 so that it may become 5:17?

Answers

Answered by williamchris2007
0

Answer:

16*3 = 48 and 24*2 = 48

Step-by-step explanation:

We have the two ratios and they need to be equal, so

27:35::2:3.

Multiply the means and multiply the extremes, thus 27*3 = 81 and 35*2 = 70 the excess of one over the other is 81–70 or 11. Hence deduct 11 from each term of the fraction so that it becomes (27–11)/(35–11) = 16/24 which is the same as the ratio desired.

Check: 16:24::2:3. Here 16*3 = 48 and 24*2 = 48 hence correct.

Answered by tiwariakdi
0

-2 must be added to the numerator and -14 must be added to the denominator to get the required fraction.

  • An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
  • Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information,

Let x be added to the numerator and let y be added to the denominator.

Then, 7 + x = 5.

Or, x = 5 - 7 = -2.

Again, 31 + y = 17

Or, y = 17 - 31 = -14.

Hence, -2 must be added to the numerator and -14 must be added to the denominator to get the required fraction.

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https://brainly.in/question/48534636

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