what number must be added to 3x³-4x²-5x so that the resulting polynomial has a factor x-2
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Answer:
x - 3 = 0
0x = 3 + 0
0x = 3
0x = 3Le, the number to be added be y
f ( 3) = 3 (3³}³3 ) - 5 (3²}3 2 ) + 6 ( 3 ) + y = 8
) + 6 ( 3 ) + y = 8= 81 -45 + 18 - 8 + y = 0
) + 6 ( 3 ) + y = 8= 81 -45 + 18 - 8 + y = 0= 46 + y = 0
) + 6 ( 3 ) + y = 8= 81 -45 + 18 - 8 + y = 0= 46 + y = 0y = - 46
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