what number must be added to 8,12,14,and 20 to get the number which are in priportional
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let the no. added be X
so (8+X):(12+X)::(14+X):(20+X)
as we know product of means = product of extremes .
so,
(12+X)(14+X) = (8+X)(20+X)
168+12x+14x+x² = 160+8x+20x+x²
168+26x+x² = 160+28x+x²
168-160 + x²-x² = 28x-26x
8 = 2x
8/2 = X
4 = X
hence, the number added to the following numbers is 4
so,
(8+X):(12+X)::(14+X):(20+X) =
(8+4):(12+4)::(14+4):(20+4)
12:16::18:24
hope it will help you....
please mark as brainliest...
so (8+X):(12+X)::(14+X):(20+X)
as we know product of means = product of extremes .
so,
(12+X)(14+X) = (8+X)(20+X)
168+12x+14x+x² = 160+8x+20x+x²
168+26x+x² = 160+28x+x²
168-160 + x²-x² = 28x-26x
8 = 2x
8/2 = X
4 = X
hence, the number added to the following numbers is 4
so,
(8+X):(12+X)::(14+X):(20+X) =
(8+4):(12+4)::(14+4):(20+4)
12:16::18:24
hope it will help you....
please mark as brainliest...
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